![]() ![]() So the three terms are either #24, 48, 96#, meaning that #r = 48/24 = 2#, or the terms are #24, -48, 96#, meaning that #r=-48/24 = -2#.Īfter you find #r#, you can find #a_1# the same way we did above. To find #a_4#, we can simply calculate the geometric mean. We are given #a_3# and #a_5#, so we can easily find out #a_4# in order to get the value of #r#. The common ratio is #-2#, so start with #6# and multiply each term by #-2 => 6, -12, 24, -48, 96# The common ratio is #2#, so start with #6# and multiply each term by #2 => 6, 12, 24, 48, 96# To verify if these are correct, you can write out the first few terms and see if they match the information given in the problem. Using the first equation, #color(blue)(24 = a_1 * r^2)#, we get Now that we have the value of #r#, we can find the value of #a_1#. #96=24/r^2 * r^4#-># substitute the value of #a_1# into the second equation Now we can solve the system of equations: Since we are given #a_3 = 24# and #a_5 = 96#, we can substitute them into the formula. Nth term equation maker how to#I'm going to explain how to do this problem two ways. ![]() Other equation types to know are the biquadratic, rational, logarithmic, and absolute.The general formula for a geometric sequence is #a_n = a_1 * r^(n-1)#, where #a_n# is the #n^(th)# term, #a_1# is the first term, and #r# is the common ratio. The key to solving equations is to identify the equation type. One more thing to note, by squaring the equation we changed the original equation, so it is very important to check the solutions at the end. To solve radical equations, you first have to get rid of the radicals, in the case of square roots square both sides of the equation (in some cases this should be done multiple times), then simplify the new equation (either linear or quadratic) and solve. Radical equations are equations involving radicals of any order. The logarithm property ln(a^x)=xln(a) makes this a fairly simple task. In all other cases, take the log of both sides (this might require some manipulation) and solve for the variable.If the exponents on both sides of the equation have the same base, you can use the fact that: If a^x=a^y then x=y.Solving exponential equations is straightforward there are basically two techniques: The quadratic formula comes in handy, all you need to do is to plug in the coefficients and the constants (a,b and c). To make things simple, a general formula can be derived such that for a quadratic equation of the form ax²+bx+c=0 the solutions are x=(-b ± sqrt(b^2-4ac))/2a. Take the square root of each side and solve. Take half of the coefficient of the middle term(x), square it, and add that value to both sides of the equation. Move the constant term to the right hand side. Easy is good, so we basically want to force the quadratic equation into the form (x+a)²=x²+2ax+a².Īll it takes is making sure that the coefficient of the highest power (x²) is one. The equation -x -5 says that the additive inverse of x is -5. When each side is divided by 4, only the result is written. However, when 5 is added to each side in the solution on the left, only the result is written. But what if the quadratic equation can’t be factored, you're going to need a different method to help you solve it, completing the square.Īn equation in which one side is a perfect square trinomial can be easily solved by taking the square root of each side. The same steps are used in each of the solutions. Solving quadratics by factorizing usually works just fine. How do you factorize a quadratic? The trick is to get the equation to the form (x-u)(x-v)=0, now we have to solve much simpler equations. There are multiple methods to solve quadratics: factorization, completing the square, and the quadratic formula.įirst up is factorization. Remember, whatever you do to one side of the equation, you must do the same to the other side.Ī quadratic equation is a second-degree polynomial having the general form ax²+bx+c=0, where a, b, and c are constants. You do this by adding, subtracting, multiplying or dividing both sides of the equation. The trick here to solving the equation is to end up with x on one side of the equation and a number on the other. ![]() You have an equation with one unknown - call it x. Solving equations involves finding the unknowns in the equation. ![]()
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